Work,Energy+&+Circular+Motion+Collaborative+Page

= Welcome to the Work, Energy and Circular Motion Collaborative Page = =

= = Huge gamma-ray bubbles found extending from Milky Way = The unexpected discovery suggests a colossal event in our galaxy's past, releasing energy equivalent to 100,000 exploding stars. But scientists don't yet know what that event might have been. []



The energy emitted in this case comes in several forms; light, nuclear, kinetic, radiation. The main way stellar bodies release energy is through light. The energy of light rays depend on their wavelength. The smaller the wavelength, the greater the energy. Blue light has more energy than red light because it has a smaller wavelength. In the case of the energy bubbles, the type of "light" released is x-rays and gamma rays. This type of light has an extremely small wavelength (~1 x 10 -16 m or 0.0000000000000001m long) so it has a huge energy. If such an energy bubble were to come close to earth, we would all be wiped out.

Mr.Brehmer
Garrett WIKI Circular Motion of 22's

To find the height of the building you take two angles from 2 locations. Then measure your base line and the height of your eye. Then take your data and put it into the follow formula. h__= (sin(24)sin(33)__ x 20m) + 6.1 Sin(9) And the height of the building is= 34.4 m by: trevor

For motion in a circle of radius R, the circumference of the circle is //C// = 2π //R//. If the period for one rotation is //T//, the angular rate of rotation, also known as angular velocity, ω is: The speed of the object traveling the circle is: The angle θ swept out in a time //t// is: The acceleration due to change in the direction of the velocity is found by noticing that the velocity completely rotates direction in the same time //T// the object takes for one rotation. Thus, the velocity vector sweeps out a path of length 2π //v// every //T// seconds, or: and is directed //radially inward//. By: Eric

In this picture it displays horizontal circular motion. It states that the radius is 0.5m and that the velocity is 10 m/s. If you are given the velocity and the radius you can find the Centripetal Force (FC) by using the formula **//__Fc=1/2(m) (v) ^2 / (r)__//**__.__ Before you use this formula, you would have to use the formula Fc = (m) (g), in order to cancel out the mass. You would now use the formula **//__Fc=1/2(v) ^2/(r)__//** to figure out the Centripetal Force. By: Kevin Murphy



This amusement park ride is an example of centripetal forces. The ride goes around in a perfect circle but what holds the cart in place. Centripetal force; this force can be represented by other forces that hold an object in a circular pattern like tension or the normal force. In this case the normal force is what holds the cart in place. In order to solve for the centripetal force we must use the equation Fc= mv2/r. the mass of the cart, velocity that it moves at, and the radius of the loop are multiplied together. If the velocity is not known u can time how long it takes the ride to complete one full revolution and then use this equation. V=(2)(3.14)(r)/ T. Then use the formula for the centripetal force and the amount of force that holds the cart in its circular path can be solved. BY:Colton Weldon

**Briefing on Centripetal Force**

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In this video we can see centripetal force in 2 examples provided. The first one is the with a penny in a balloon. A balloon is blown up and a penny was placed inside. The balloon was then tied to close up any air pockets. The guy then spins the balloons causing the penny to go around the balloon. In the case the penny inside the balloon the force that acts towards the center of the circle is the normal force. The normal force is what causes the penny to keep going around and around. It will slowly come to stop due to Newton's Second thermodynamics law stating no object is 100% efficient. The efficiency lost is due to friction, some small sound etc.

The second example we did in class, except the lady on youtube failed worse than Mr.B did. A.K.A she is a noob. The major difference in this example is that gravity plays a key issue. (Gravity only has effects in the Y direction not the X.) Throughout the whole circle the centripetal force from the glasses is towards the center of the circle. The two forces at work here are the gravitational force and the tension force. Together they make up the centripetal force holding the bucket in circular motion.

By- Matthew Ankerstein