Dynamics+Collaborative+Page

2. The force generated outwards by nuclear fusion
== For our sun, these forces are roughly balanced, make Fnet = 0. In some larger older stars, this is not the case. If a large star gets very old, it can reach a stage where it has burned off much of its nuclear fuel. Stars usually burn light elements like hydrogen and helium, but in this case the star would begin to burn heavier elements in order to fight the collapsing push of gravity. This can lead to the outward fusion force become huge, causing an explosion known as a supernova. If the star is massive enough, the explosion can be followed by a large crunch as the gravitational force takes over. The star is then suddenly collapsed into the size of an atom, with close to its original mass. This point has infinite density and is known as a singularity. The gravitational strength around it is immense, and nothing, not even light, can escape its pull. This is why these systems are given the name "Black Hole". ==

[[image:http://upload.wikimedia.org/wikipedia/commons/c/cc/Airplane_2_Landing_in_Toronto.JPG width="551" height="369"]]
==This is a propeller plane, a propeller plane can move through air because as the propeller rotates, it exerts an action force on the air, pushing air backward. The air exerts a reaction force on the propeller pushing the airplane forward, this applies to Newton's third law. Newton's second law is also applied bacause the faster the propeller turns, the greater is the mass of air accelerated backward, so the force exerted by the air on the propeller increases.== By:Lindsey Hartfelder ==

This is showing that when abox is being pushed along a surface that there is friction in the opposite direction. N is equal to the normal force and the Um is how much it takes to move the box (ums is static and that is how much i takes to move the box from stand still and umk is how much it takes to move it from when it is already moving.) To find the friction force (Ff) the take the um (ums or umk)and muiltiply it by the nomal force (N or Fn).

By Trevor Fandrick



The Fn ( Normal Force) is equal to or balanced to the Fw ( weight or force of gravity). The car’s Ff (frictional force) is being affected by the tires resistance to the ground and the Fa ( Applied force) is unknown. If the car is travelling at a constant velocity or not travelling at all the applied force will be equal to the frictional force. Um is the force required to get the car moving. ( ums is the amount of force required to get the car moving from a standstill and umk is the amount of force required to get the car moving when it is already in motion). To find the friction force the take the um (ums or umk)and multiply it by the normal force.



== If the mass of the moon is 7.35 x 10ˆ22 kg, while earth’s is 5.97 x 10ˆ24 kg, we can figure out the gravitational force acting between them. We would accomplish this by using the equation, Fg=Gm1m2/r2. We also know that the gravitational constant is 6.67300 × 10-11 N*m2/kg2. To find the answer, you would multiply the gravitational constant and the two masses of the planets. After finding the sum, you would divide the product by the radius, or distance between the two objects. Remember, the distance is from the middle of the moon to the middle of the earth. ==

Joshua Critch

to find the tension of the object at the end of the rope i will need to find the acceleration and then the tension. you will figure out the Fg of of both of the objects which I will use fg= mg. then i will find the Fnet of the objects by using Fnet= Fg1- Fg2. then i can find the acceleration by using the (Msys)(Asys)=19.62 that will which will give me the acceleration of the system. now i will use the equation Fnet of one of the objects so i will use Fnet= Ft- Fg1. this equation will give me the tension on the rope of the system by the two oblects.

Mac Morgan



A Calgary flames player ( I know his name just not how to spell it) has a hard slap shot. His slap shot can reach high rate of speeds due to the force being applied being greater than the friction force. The applied force would be the motion that is transferred from the player through his stick to the puck. The puck stays stationary until it is shot because the force of friction is the same as the applied force (this is seen when the puck is not moving), and the puck doesn’t levitate because the normal force is the same as the force of gravity. In the players shot, the puck moves because the forces become unbalanced and the speed of the puck is determined by the amount of applied force. By: Colton Weldon

Hockey Fights


Above we have the classic Hanson brothers from the movie Slapshot. The Hanson brothers are violent goons with childlike mentalities. If one of the Hanson brothers were to get into a fight, how can he give off a harder punch than his opponent? F=ma. (Force equals the mass times the acceleration) If one of the Hanson’s got into a fight they would have to have 1 of 2 things in order to throw a harder punch. One is that the Hanson brother would have to have a higher acceleration throughout his punch than his opponent. Or the Hanson brother would have to have a way higher mass than his opposition. We also have 2 other forces. Those 2 forces would be the force of gravity and the normal force. In this case these 2 forces would be equal to each otherwise the players fighting would be falling through the ice.

By: Matthew Ankerstein



Opossums are considered marsupials, and are the largest order of this found in the western hemisphere. They are commonly called possums and are known for their abilities to "play dead" and to hang by their tales. The opossums ability to hang by their tail is however false, except for in the case of their babies; for when a opossum ages its mass becomes too great for its tail to support them. Therefore the force of gravity is greater than the force of tension. To calculate the force of tension we use Fnet = FT + Fg

The force of tension acting upon a baby opossums tail is: ma= FT + Fg (0.226796185 kg)(0) = FT + (0.226796185 kg)(-9.81) 0 = FT – 2.22487057485 FT = 2.22487057485 N The force of tension in a baby opossums tail is __2.22 N__ Fg = mg = (0.226796185 kg)(-9.81) = – 2.22487057485 N By: Maria Makepeace

By rearranging the formula Fnet/m=a we can find the acceleration “superman” would need in order to lift a car weighing 1000 kg with a net force of 2500 N. M=1000kg Fnet=2500 N a= ? 2500 N/ 1000 Kg=a 2.5 m/s 2=a

Paige Worms
===Jenn Buss=== ===Joe Brower Minoch one of the world's heaviest people, weighing in at 635 kg in 1978. To find out what he would weigh on earth the formula would be W=mg. G being 9.81 (acceleration due to gravity on earth). He would weigh 6229.35N on earth. To find out how much less he would weigh on the moon compared to on earth you would take his mass and multiply it by the acceleration due to gravity on the moon (1.61m/s2). The formula being the same as before (w=mg). To find out the force of gravity of Joe on the moon you would use f=Gm1m2/r2(squared) gbeing (6.67x10-11) m1 being the mass of Joe (635kg) and the mass of the moon being (7.24x10^22kg) and r2 being (1.74x10^6m). All you would have to do from there is plug the values into the formula. Any way you look at it Joe is a big guy.===



If the tiger runs to the person from rest to a velocity of 40m/s in a time of 25s what is the acceleration of the tiger? You would use the formula a=v**/**t The work would be a=40m/s**/**25s and a would equal a= 1.6m/s2

VICTORIA POPIK